A ladder has rungs 25cm apart. The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are ${\text{2}}\dfrac{1}{2}{\text{m}}$apart, then what is the length of the wood required for the rungs?
Answer
689.4k+ views
Hint: -Length of the rungs decrease uniformly therefore they will form an A.P.
According to the question it is given that the rungs are 25cm apart and the top and bottom rungs are ${\text{2}}\dfrac{1}{2}{\text{m}}$apart.
$ \Rightarrow {\text{2}}\dfrac{1}{2}m = \dfrac{5}{2}m = \dfrac{{500}}{2}cm = 250cm.\left[ {\because {\text{ 1m = 100cm}}} \right]$
$\therefore $Total number of rungs${\text{ = }}\dfrac{{{\text{Distance between total rungs}}}}{{{\text{Distance between two rungs}}}} + 1$, (plus one because of the bottom rung and thereafter all rungs are 25 cm apart).
$\therefore $Total number of rungs${\text{ = }}\dfrac{{250}}{{25}} + 1 = 11$
Now as the length of the rungs decrease uniformly therefore they will form an A.P.
So the A.P becomes $\left( {45,.................,25} \right)$
So, first term $\left( {{a_1}} \right)$of an A.P${\text{ = 45}}$, last term $\left( {{a_n}} \right)$of an A.P${\text{ = 25}}$, and number of terms in this A.P$ = 11$
Now, as we know last term of this series is written as
${a_n} = {a_1} + \left( {n - 1} \right)d$, Where d is the common difference.
$ \Rightarrow d = \dfrac{{{a_n} - {a_1}}}{n} + 1 = \dfrac{{25 - 45}}{{11}} + 1 = \dfrac{{ - 20}}{{11}} + 1 = \dfrac{{ - 9}}{{11}}$
So, the length of the rungs decrease uniformly by $\dfrac{{ - 9}}{{11}}cm$
The length of the wood required for the rungs equals the sum of all the terms of this A.P
${S_n} = 45 + \left( {45 - \dfrac{9}{{11}}} \right) + \left( {45 - \dfrac{9}{{11}} - \dfrac{9}{{11}}} \right) + .............. + 25$
Therefore sum of this A.P${\text{ = }}{{\text{S}}_n} = \dfrac{n}{2}\left( {{a_1} + {a_l}} \right)$
$ \Rightarrow {{\text{S}}_n} = \dfrac{{11}}{2}\left( {45 + 25} \right) = 11 \times 35 = 385cm$
Therefore the length of the wood required for the rungs${\text{ = 385cm}}$.
Note: -In such types of questions first find out the total numbers of rungs, then the key concept is that the length of the rungs decrease uniformly so, they will form an A.P so, the length of the wood required for the rungs equals the sum of all the terms of this A.P, so apply the formula of sum of an A.P which is stated above, we will get the required answer.
According to the question it is given that the rungs are 25cm apart and the top and bottom rungs are ${\text{2}}\dfrac{1}{2}{\text{m}}$apart.
$ \Rightarrow {\text{2}}\dfrac{1}{2}m = \dfrac{5}{2}m = \dfrac{{500}}{2}cm = 250cm.\left[ {\because {\text{ 1m = 100cm}}} \right]$
$\therefore $Total number of rungs${\text{ = }}\dfrac{{{\text{Distance between total rungs}}}}{{{\text{Distance between two rungs}}}} + 1$, (plus one because of the bottom rung and thereafter all rungs are 25 cm apart).
$\therefore $Total number of rungs${\text{ = }}\dfrac{{250}}{{25}} + 1 = 11$
Now as the length of the rungs decrease uniformly therefore they will form an A.P.
So the A.P becomes $\left( {45,.................,25} \right)$
So, first term $\left( {{a_1}} \right)$of an A.P${\text{ = 45}}$, last term $\left( {{a_n}} \right)$of an A.P${\text{ = 25}}$, and number of terms in this A.P$ = 11$
Now, as we know last term of this series is written as
${a_n} = {a_1} + \left( {n - 1} \right)d$, Where d is the common difference.
$ \Rightarrow d = \dfrac{{{a_n} - {a_1}}}{n} + 1 = \dfrac{{25 - 45}}{{11}} + 1 = \dfrac{{ - 20}}{{11}} + 1 = \dfrac{{ - 9}}{{11}}$
So, the length of the rungs decrease uniformly by $\dfrac{{ - 9}}{{11}}cm$
The length of the wood required for the rungs equals the sum of all the terms of this A.P
${S_n} = 45 + \left( {45 - \dfrac{9}{{11}}} \right) + \left( {45 - \dfrac{9}{{11}} - \dfrac{9}{{11}}} \right) + .............. + 25$
Therefore sum of this A.P${\text{ = }}{{\text{S}}_n} = \dfrac{n}{2}\left( {{a_1} + {a_l}} \right)$
$ \Rightarrow {{\text{S}}_n} = \dfrac{{11}}{2}\left( {45 + 25} \right) = 11 \times 35 = 385cm$
Therefore the length of the wood required for the rungs${\text{ = 385cm}}$.
Note: -In such types of questions first find out the total numbers of rungs, then the key concept is that the length of the rungs decrease uniformly so, they will form an A.P so, the length of the wood required for the rungs equals the sum of all the terms of this A.P, so apply the formula of sum of an A.P which is stated above, we will get the required answer.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

