A toy store marks down every toy by \[15\% \] in January. How much does a toy cost during January, using \[p\] for the price in December?
Answer
607.2k+ views
Hint: In this question, we are given the price of toys in December. We are asked to find the cost of toys in January after there is a discount of \[15\% \] . For this, we need to use the formula to determine the sales price after the discount and as a result we will get the price of toys in January in terms of the price of toys in December that is \[p\] .
Formula used:
\[s = p(1 - d)\] , where, \[s\] is the sales price of the month when the discount is applied, \[p\] is the price of the previous month after which the discount is applied and \[d\] is the discount.
Complete step by step solution:
We are given the price of the December for the toys is \[p\] .
The toy store marks down every toy by \[15\% \] in January, therefore we will take $d = \dfrac{{15}}{{100}}$.
We need to find the cost of the toy in the month January which will be the sales price of January \[s\] .
Now, we will apply the formula for the sales price and then put these values in that formula.
\[
s = p(1 - d) \\
\Rightarrow s = p\left( {1 - \dfrac{{15}}{{100}}} \right) = p\left( {1 - 0.15} \right) = 0.85p \;
\]
Thus, the cost of the toy \[0.85p\] in the month of January after applying the discount, considering that \[p\] is the price of the toy in the month of December.
Note: In solving this type of question, we need to be careful while putting the value of the discount. We know that percentage means out of hundred. This means that we cannot put 15 as the value of discount in this problem. Instead, we need to put its value as $\dfrac{{15}}{{100}}$.
Formula used:
\[s = p(1 - d)\] , where, \[s\] is the sales price of the month when the discount is applied, \[p\] is the price of the previous month after which the discount is applied and \[d\] is the discount.
Complete step by step solution:
We are given the price of the December for the toys is \[p\] .
The toy store marks down every toy by \[15\% \] in January, therefore we will take $d = \dfrac{{15}}{{100}}$.
We need to find the cost of the toy in the month January which will be the sales price of January \[s\] .
Now, we will apply the formula for the sales price and then put these values in that formula.
\[
s = p(1 - d) \\
\Rightarrow s = p\left( {1 - \dfrac{{15}}{{100}}} \right) = p\left( {1 - 0.15} \right) = 0.85p \;
\]
Thus, the cost of the toy \[0.85p\] in the month of January after applying the discount, considering that \[p\] is the price of the toy in the month of December.
Note: In solving this type of question, we need to be careful while putting the value of the discount. We know that percentage means out of hundred. This means that we cannot put 15 as the value of discount in this problem. Instead, we need to put its value as $\dfrac{{15}}{{100}}$.
Recently Updated Pages
Find the greatest six digit number that is exactly class 8 maths CBSE

What is the time difference between India and Cana class 8 social science CBSE

Compare LPG and wood as fuels class 8 chemistry CBSE

In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

30 opposite words in English from a to z class 8 english CBSE

How many cubic feet equals to 1 unit sand class 8 maths CBSE

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

One cusec is equal to how many liters class 8 maths CBSE

What are the methods of reducing friction. Explain

What is the difference between rai and mustard see class 8 biology CBSE


