A washing machine was bought as \[Rs.{\text{ }}15,625\] three years ago, if its value
depreciates at 16% p.a., calculate
(iii) Its present value;
(iv) Its value after one year from now.
Answer
652.8k+ views
Hint: Find the present value of the washing machine using the formula given below:
Present value$ = {\text{Cost price}}{\left( {1 - \dfrac{{{\text{rate per annum}}}}{{100}}}
\right)^t}$
Substitute the values and get the desired result.
It is given that three years ago, a washing machine was bought\[Rs.{\text{ }}15,625\]. It is also
given that its value depreciates at 16% p.a.
We have to find the present value of the washing machine and its value after one year from now.
We have given, the cost price three years ago, the rate of depreciation and the time as:
Cost price$ = Rs.15,625$
Rate per annum$ = 16\% $ p.a.
Time$ = 3$years
Then the present value of the washing machine can be given as:
Present value$ = {\text{Cost price}}{\left( {1 - \dfrac{{{\text{rate per annum}}}}{{100}}}
\right)^t}$
Substitute the values of the cost price three years ago, the rate of depreciation and the time so we
have the present value as:
Present value$ = 15625{\left( {1 - \dfrac{{{\text{16}}}}{{100}}} \right)^3}$
Present value$ = 15625{\left( {\dfrac{{84}}{{100}}} \right)^3}$
Present value$ = 15625{\left( {\dfrac{{21}}{{25}}} \right)^3}$
Present value$ = 15625\left( {\dfrac{{21 \times 21 \times 21}}{{25 \times 25 \times 25}}}
\right)$
Present value$ = 9261$
Therefore, the present value of the washing machine is Rs.$9261$.
Now, the present cost price of the washing machine is Rs.$9261$, so the value of the washing
machine after the one year is given as:
Value of Machine after one year$ = 9261{\left( {1 - \dfrac{{16}}{{100}}} \right)^1}$
Value of Machine after one year$ = 9261\left( {\dfrac{{84}}{{100}}} \right)$
Value of Machine after one year$ = 9261\left( {\dfrac{{21}}{{25}}} \right)$
Value of Machine after one year$ = 7779.24$
Therefore, the value of the washing machine after one year is Rs.$7779.24$.
Note: When we find the value of the machine after one year from now, we use the cost price of
the washing machine at the present time that was obtained in the part (i).
Present value$ = {\text{Cost price}}{\left( {1 - \dfrac{{{\text{rate per annum}}}}{{100}}}
\right)^t}$
Substitute the values and get the desired result.
It is given that three years ago, a washing machine was bought\[Rs.{\text{ }}15,625\]. It is also
given that its value depreciates at 16% p.a.
We have to find the present value of the washing machine and its value after one year from now.
We have given, the cost price three years ago, the rate of depreciation and the time as:
Cost price$ = Rs.15,625$
Rate per annum$ = 16\% $ p.a.
Time$ = 3$years
Then the present value of the washing machine can be given as:
Present value$ = {\text{Cost price}}{\left( {1 - \dfrac{{{\text{rate per annum}}}}{{100}}}
\right)^t}$
Substitute the values of the cost price three years ago, the rate of depreciation and the time so we
have the present value as:
Present value$ = 15625{\left( {1 - \dfrac{{{\text{16}}}}{{100}}} \right)^3}$
Present value$ = 15625{\left( {\dfrac{{84}}{{100}}} \right)^3}$
Present value$ = 15625{\left( {\dfrac{{21}}{{25}}} \right)^3}$
Present value$ = 15625\left( {\dfrac{{21 \times 21 \times 21}}{{25 \times 25 \times 25}}}
\right)$
Present value$ = 9261$
Therefore, the present value of the washing machine is Rs.$9261$.
Now, the present cost price of the washing machine is Rs.$9261$, so the value of the washing
machine after the one year is given as:
Value of Machine after one year$ = 9261{\left( {1 - \dfrac{{16}}{{100}}} \right)^1}$
Value of Machine after one year$ = 9261\left( {\dfrac{{84}}{{100}}} \right)$
Value of Machine after one year$ = 9261\left( {\dfrac{{21}}{{25}}} \right)$
Value of Machine after one year$ = 7779.24$
Therefore, the value of the washing machine after one year is Rs.$7779.24$.
Note: When we find the value of the machine after one year from now, we use the cost price of
the washing machine at the present time that was obtained in the part (i).
Recently Updated Pages
What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

A Paragraph on Pollution in about 100-150 Words

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

Name 10 Living and Non living things class 9 biology CBSE

What is the full form of pH?

On an outline map of India show its neighbouring c class 9 social science CBSE

What is pollution? How many types of pollution? Define it

