Find $\angle ADC$ from the given figure.
Answer
680.4k+ views
Hint:Find the angle ADC (reflex) which is a reflex angle and forming inside the quadrilateral ABCD. Sum of all the angles of a quadrilateral is \[{{360}^{\circ }}\]. And angle around a point is \[{{360}^{\circ }}\] as well. Calculate the angle ADC as required in the question, using above information.
Complete step-by-step answer:
Given diagram in question is
As we know, the sum of all the interior angles of a quadrilateral is \[{{360}^{\circ }}\]. And we observe that ABCD is also a quadrilateral as it has four sides. So, the sum of all the angles of it will be \[{{360}^{\circ }}\] as well. So, we can write the equation as
\[\angle BAD+\angle ABC+\angle BCD+\angle ADC\] (reflex or inside of quadrilateral) = \[{{360}^{\circ }}\]
So, put the values of angles given in the diagram so, we get
\[30+55+50+\angle ADC\ \left( \text{reflex} \right)\ =\ {{360}^{\circ }}\]
\[135+\angle ADC\ \left( \text{reflex} \right)\ =\ {{360}^{\circ }}\]
\[\angle ADC\ \left( \text{reflex} \right)=\ 360-135\]
\[\angle ADC\ \left( \text{reflex} \right)\ =\ {{225}^{\circ }}\]
Hence, angle ADC (reflex) inside the quadrilateral is \[{{225}^{\circ }}\].
Now, as we know that angle formed around a point is \[{{360}^{\circ }}\], as we need to rotate \[{{360}^{\circ }}\]. Hence, the sum of angles ADC (reflex) and ADC (outer of quadrilateral) is \[{{360}^{\circ }}\]. And we need to calculate \[\angle ADC\] (outer) from the problem.
So, we can write equation as
\[\angle ADC\ \left( \text{reflex} \right)+\angle ADC\ \left( \text{outer} \right)\ =\ {{360}^{\circ }}\]
\[{{225}^{\circ }}+\angle ADC\ \left( \text{outer} \right)\ =\ {{360}^{\circ }}\]
\[\angle ADC\ \left( \text{outer} \right)\ =\ {{360}^{\circ }}-{{225}^{\circ }}\]
\[=\ {{135}^{\circ }}\]
Hence, the value of \[\angle ADC\] lying on the outer side of the quadrilateral is \[{{135}^{\circ }}\].
Note: Observing ABCD as a quadrilateral is the key point of the question and take the sum of angles of a quadrilateral as \[{{360}^{\circ }}\] not \[{{180}^{\circ }}\]. Sum of interior angles of n sided polygon is given as
$=\ \left( n-2 \right)\times {{180}^{\circ }}$
Don’t confuse with the reflex angle term used in the solution. It is used to define that angle ADC inside the quadrilateral has higher angle than \[{{180}^{\circ }}\], as Reflex angle is defined as angles between \[{{180}^{\circ }}\] and \[{{360}^{\circ }}\] are reflex angles.
Complete step-by-step answer:
Given diagram in question is
As we know, the sum of all the interior angles of a quadrilateral is \[{{360}^{\circ }}\]. And we observe that ABCD is also a quadrilateral as it has four sides. So, the sum of all the angles of it will be \[{{360}^{\circ }}\] as well. So, we can write the equation as
\[\angle BAD+\angle ABC+\angle BCD+\angle ADC\] (reflex or inside of quadrilateral) = \[{{360}^{\circ }}\]
So, put the values of angles given in the diagram so, we get
\[30+55+50+\angle ADC\ \left( \text{reflex} \right)\ =\ {{360}^{\circ }}\]
\[135+\angle ADC\ \left( \text{reflex} \right)\ =\ {{360}^{\circ }}\]
\[\angle ADC\ \left( \text{reflex} \right)=\ 360-135\]
\[\angle ADC\ \left( \text{reflex} \right)\ =\ {{225}^{\circ }}\]
Hence, angle ADC (reflex) inside the quadrilateral is \[{{225}^{\circ }}\].
Now, as we know that angle formed around a point is \[{{360}^{\circ }}\], as we need to rotate \[{{360}^{\circ }}\]. Hence, the sum of angles ADC (reflex) and ADC (outer of quadrilateral) is \[{{360}^{\circ }}\]. And we need to calculate \[\angle ADC\] (outer) from the problem.
So, we can write equation as
\[\angle ADC\ \left( \text{reflex} \right)+\angle ADC\ \left( \text{outer} \right)\ =\ {{360}^{\circ }}\]
\[{{225}^{\circ }}+\angle ADC\ \left( \text{outer} \right)\ =\ {{360}^{\circ }}\]
\[\angle ADC\ \left( \text{outer} \right)\ =\ {{360}^{\circ }}-{{225}^{\circ }}\]
\[=\ {{135}^{\circ }}\]
Hence, the value of \[\angle ADC\] lying on the outer side of the quadrilateral is \[{{135}^{\circ }}\].
Note: Observing ABCD as a quadrilateral is the key point of the question and take the sum of angles of a quadrilateral as \[{{360}^{\circ }}\] not \[{{180}^{\circ }}\]. Sum of interior angles of n sided polygon is given as
$=\ \left( n-2 \right)\times {{180}^{\circ }}$
Don’t confuse with the reflex angle term used in the solution. It is used to define that angle ADC inside the quadrilateral has higher angle than \[{{180}^{\circ }}\], as Reflex angle is defined as angles between \[{{180}^{\circ }}\] and \[{{360}^{\circ }}\] are reflex angles.
Recently Updated Pages
Write any three differences between metals and nonmetals class 10 social science CBSE

Amit standing on a horizontal plane finds a bird flying class 10 maths CBSE

Two circles of radii 5 cm and 3 cm intersect at two class 10 maths CBSE

Solve the following i John and Jivanti together have class 10 maths CBSE

What is the relation between orthocenter circumcentre class 10 maths CBSE

Two plane mirrors are inclined at 70circ A ray incident class 10 physics CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Which country is known as "The land of Fire and Ice"?

1 GB equals how many MB?

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Which is the hottest planet in the Solar system A Earth class 10 social science CBSE

