How do you factor completely $36{x^2} - 25$ ?
Answer
624.6k+ views
Hint:To order to determine the factors of the above quadratic equation using the identity $\left( {{A^2} - {B^2}} \right) = \left( {A - B} \right)\left( {A + B} \right)$
Complete step by step solution:
Given a quadratic equation $36{x^2} - 25$,let it be $f(x)$
$f(x) = 36{x^2} - 25$
Comparing the equation with the standard Quadratic equation
a becomes 36
b becomes 0
And c becomes -25
To find the quadratic factorization we’ll be writing the expression as
$f\left( x \right) = {(6x)^2} - {(5)^2}$
Consider $6x$as A and $5$as B and Applying Identity $\left( {{A^2} - {B^2}} \right) = \left( {A - B} \right)\left( {A + B} \right)$
Now our equation becomes
$f\left( x \right) = (6x - 5)(6x + 5)$
Hence, We have successfully factorized our quadratic equation.
Therefore, the factors are$(6x - 5)$ and$(6x + 5)$
Alternative:
You can also alternatively use a direct method which uses Quadratic Formula to find both roots of a quadratic equation as
$x1 = \dfrac{{ - b + \sqrt {{b^2} - 4ac} }}{{2a}}$ and $x2 = \dfrac{{ - b - \sqrt {{b^2} - 4ac} }}{{2a}}$
x1,x2 are root to quadratic equation $a{x^2} + bx + c$
Hence the factors will be $(x - x1)\,and\,(x - x2)\,$.
Additional Information:
Quadratic Equation: A quadratic equation is an equation which can be represented in the form of $a{x^2} + bx + c$ where $x$ is the unknown variable and a,b,c are the numbers known where $a \ne 0$. If $a = 0$then the equation will become a linear equation and will no longer be quadratic .
The degree of the quadratic equation is of the order 2.
Every Quadratic equation has 2 roots.
Discriminant: $D = {b^2} - 4ac$
Using Discriminant, we can find out the nature of the roots
If D is equal to zero, then both of the roots will be the same and real.
If D is a positive number then, both of the roots are real solutions.
If D is a negative number, then the root are the pair of complex solutions
Note: 1. One must be careful while calculating the answer as calculation error may come.
2.Don’t forget to compare the given quadratic equation with the standard one every time.
Complete step by step solution:
Given a quadratic equation $36{x^2} - 25$,let it be $f(x)$
$f(x) = 36{x^2} - 25$
Comparing the equation with the standard Quadratic equation
a becomes 36
b becomes 0
And c becomes -25
To find the quadratic factorization we’ll be writing the expression as
$f\left( x \right) = {(6x)^2} - {(5)^2}$
Consider $6x$as A and $5$as B and Applying Identity $\left( {{A^2} - {B^2}} \right) = \left( {A - B} \right)\left( {A + B} \right)$
Now our equation becomes
$f\left( x \right) = (6x - 5)(6x + 5)$
Hence, We have successfully factorized our quadratic equation.
Therefore, the factors are$(6x - 5)$ and$(6x + 5)$
Alternative:
You can also alternatively use a direct method which uses Quadratic Formula to find both roots of a quadratic equation as
$x1 = \dfrac{{ - b + \sqrt {{b^2} - 4ac} }}{{2a}}$ and $x2 = \dfrac{{ - b - \sqrt {{b^2} - 4ac} }}{{2a}}$
x1,x2 are root to quadratic equation $a{x^2} + bx + c$
Hence the factors will be $(x - x1)\,and\,(x - x2)\,$.
Additional Information:
Quadratic Equation: A quadratic equation is an equation which can be represented in the form of $a{x^2} + bx + c$ where $x$ is the unknown variable and a,b,c are the numbers known where $a \ne 0$. If $a = 0$then the equation will become a linear equation and will no longer be quadratic .
The degree of the quadratic equation is of the order 2.
Every Quadratic equation has 2 roots.
Discriminant: $D = {b^2} - 4ac$
Using Discriminant, we can find out the nature of the roots
If D is equal to zero, then both of the roots will be the same and real.
If D is a positive number then, both of the roots are real solutions.
If D is a negative number, then the root are the pair of complex solutions
Note: 1. One must be careful while calculating the answer as calculation error may come.
2.Don’t forget to compare the given quadratic equation with the standard one every time.
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