How do you solve $w+6=2\left( w-6 \right)$?

Hint: We separate the variables and the constants of the equation $w+6=2\left( w-6 \right)$. We have one multiplication. We multiply the constant. Then we apply the binary operation of addition and subtraction for both variables and constants. We solve the linear equation to find the value of $w$.

Complete step-by-step solution:
The given equation $w+6=2\left( w-6 \right)$ is a linear equation of $w$. We need to simplify the equation by completing the multiplication of the constants separately.
All the terms in the equation of $w+6=2\left( w-6 \right)$ are either variables of $w$ or a constant. We break the multiplication by multiplying 2 with $\left( w-6 \right)$.
So, $2\left( w-6 \right)=2w-12$. The equation becomes $w+6=2w-12$.
We take all the variables and the constants on one side and get $w+6-2w+12=0$.
There are two variables which are $w,-2w$.
The binary operation between them is addition which gives us $w-2w=-w$.
Now we take the constants. There are two such constants which are $6,12$.
The binary operation between them is addition which gives us $6+12=18$.
The final solution becomes
$\begin{align}
  & w+6-2w+12=0 \\
 & \Rightarrow -w+18=0 \\
\end{align}$.
Now we take the variable on one side and the constants on the other side.
\[\begin{align}
  & -w+18=0 \\
 & \Rightarrow w=18 \\
\end{align}\]
Therefore, the solution is $w=18$.

Note: We verify the result of the equation $w+6=2\left( w-6 \right)$ by taking the value of $w$ as $w=18$.
Therefore, the left-hand side of the equation becomes $w+6=18+6=24$
The right-hand side of the equation becomes $2\left( w-6 \right)=2\left( 18-6 \right)=24$.
Thus, verified for the equation $w+6=2\left( w-6 \right)$ the solution is $w=18$.