In the pulley system shown in the figure, if radii of bigger and smaller pulley are $2\;{\rm{m}}$ and $1\;{\rm{m}}$ respectively and acceleration of block A is $5\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$in the downward direction, then the acceleration of block B will be,
A. $0\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
B. $5\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
C. $10\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
D. ${\rm{5/2}}\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
Answer
642.9k+ views
Hint: In the solution we will use the relation between the linear acceleration and angular acceleration. Also, there is no need to draw a free body diagram and calculate the force acting on both the blocks. We will also use the concept of a rotating body about a fixed axis in which each particle has the same angular velocity and angular acceleration.
Complete step by step answer:
Given:
The radius of the smaller pulley is, $r = 1\;{\rm{m}}$.
The radius of the bigger pulley is,$R = 2\;{\rm{m}}$
The acceleration of block A is,${a_{\rm{A}}} = 5\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
The relation between linear and angular acceleration is,
$a = \alpha r$
Angular acceleration of block A is,
${\alpha _{\rm{A}}} = \dfrac{{{a_{\rm{A}}}}}{R}$ … (i)
Angular acceleration of block B is,
${\alpha _{\rm{B}}} = \dfrac{{{a_{\rm{B}}}}}{r}$ … (ii)
As both the pulleys are pivoted at the same point and connected to each other, thus both the pulleys have the same angular velocity and angular acceleration.
$
{\alpha _{\rm{A}}} = {\alpha _{\rm{B}}}\\
\Rightarrow\dfrac{{{a_{\rm{A}}}}}{R} = \dfrac{{{a_{\rm{B}}}}}{r}$
Rearranging the above terms,
${a_{\rm{B}}} = \dfrac{{{a_{\rm{A}}}r}}{R}$
Substitute the necessary values and calculate the linear acceleration of block B,
$
{a_{\rm{B}}} = \dfrac{{\left( {5\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \cdot \left( {1\;{\rm{m}}} \right)}}{{2\;{\rm{m}}}}\\
\therefore {a_{\rm{B}}} = \dfrac{5}{2}\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
Thus, the acceleration of block B is $\dfrac{5}{2}\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$. Hence option D is the correct answer.
Note:Make sure to use the concept of rotational motion that both the pulleys have the same acceleration to get the appropriate result and also remember that the linear acceleration of both the blocks are depend upon the distance of block from the pivoted point thus block A have more linear acceleration than block B.
Complete step by step answer:
Given:
The radius of the smaller pulley is, $r = 1\;{\rm{m}}$.
The radius of the bigger pulley is,$R = 2\;{\rm{m}}$
The acceleration of block A is,${a_{\rm{A}}} = 5\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
The relation between linear and angular acceleration is,
$a = \alpha r$
Angular acceleration of block A is,
${\alpha _{\rm{A}}} = \dfrac{{{a_{\rm{A}}}}}{R}$ … (i)
Angular acceleration of block B is,
${\alpha _{\rm{B}}} = \dfrac{{{a_{\rm{B}}}}}{r}$ … (ii)
As both the pulleys are pivoted at the same point and connected to each other, thus both the pulleys have the same angular velocity and angular acceleration.
$
{\alpha _{\rm{A}}} = {\alpha _{\rm{B}}}\\
\Rightarrow\dfrac{{{a_{\rm{A}}}}}{R} = \dfrac{{{a_{\rm{B}}}}}{r}$
Rearranging the above terms,
${a_{\rm{B}}} = \dfrac{{{a_{\rm{A}}}r}}{R}$
Substitute the necessary values and calculate the linear acceleration of block B,
$
{a_{\rm{B}}} = \dfrac{{\left( {5\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \cdot \left( {1\;{\rm{m}}} \right)}}{{2\;{\rm{m}}}}\\
\therefore {a_{\rm{B}}} = \dfrac{5}{2}\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$
Thus, the acceleration of block B is $\dfrac{5}{2}\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}$. Hence option D is the correct answer.
Note:Make sure to use the concept of rotational motion that both the pulleys have the same acceleration to get the appropriate result and also remember that the linear acceleration of both the blocks are depend upon the distance of block from the pivoted point thus block A have more linear acceleration than block B.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

