What is the oxidation state exhibited by boron?

Hint :Boron is a chemical element with atomic number 5 and the symbol B. It is a low-abundance element in the Solar System and the Earth's crust, produced exclusively by cosmic ray spallation and supernovae rather than stellar nucleosynthesis. It makes up around 0.001% of the Earth's crust by weight.

Complete Step By Step Answer:
The oxidation state of an atom has nothing to do with its "real" formal charge or any other atomic characteristic. This is especially true at high oxidation states, when the ionisation energy necessary to generate a multiply positive ion exceeds the energies available in chemical processes. Furthermore, depending on the electronegativity scale employed in their computation, the oxidation states of atoms in a particular molecule may differ. As a result, an atom's oxidation state in a compound is merely a formalism. It is, nevertheless, crucial to comprehending inorganic compound nomenclature standards.
The degree of oxidation of an atom in a chemical compound is determined by its oxidation state, which indicates how many electrons it has lost. The hypothetical charge that an atom would have if all of its links to other atoms were fully ionic in nature may be described as the oxidation state of that atom.
Boron has an oxidation state of +1. The ionisation enthalpy of boron is high due to its tiny size. This keeps it from forming +3 ions.

Note :
Because the pure substance is exceedingly difficult to manufacture, element boron is uncommon and poorly understood. The majority of "boron" research uses materials with trace levels of carbon. Boron's chemical behaviour is more similar to that of silicon than that of aluminium. The chemical inertness of crystalline boron makes it resistant to attack by boiling hydrofluoric or hydrochloric acid. Hot concentrated hydrogen peroxide, hot concentrated nitric acid, hot sulfuric acid, or a hot combination of sulfuric and chromic acids attack it slowly when finely split.