Similar to electron diffraction, a neutron diffraction microscope is also used for the determination of the structure of molecules. If the wavelength used here is 800 pm, calculate the characteristic velocity associated with the neutron.
Answer
646.5k+ views
Hint: There is a relationship between wavelength and velocity of the neutron.
As per de-Broglie equation the relationship is as follows.
\[\lambda =\dfrac{h}{m\times v}\text{ (}or)\text{ }v=\dfrac{h}{m\times v}\]
Where h = Planck’s constant
m = mass of the neutron
v = Velocity of the neutron
$\lambda $ = Wavelength of the neutron.
Complete step by step answer:
- In the question it is given that in a neutron diffraction microscope the wavelength used is 800 pm, and we have to calculate the characteristic velocity associated with the neutron.
- From the de-Broglie equation we can calculate the velocity of the neutron by using the wavelength of the neutron and it is as follows.
\[v=\dfrac{h}{m\times v}\]
Where h = Planck’s constant = $6.626\times {{10}^{-34}}$
m = mass of the neutron = $1.675\times {{10}^{-27}}Kg$
v = Velocity of the neutron
$\lambda $ = Wavelength of the neutron = 800 pm = $800\times {{10}^{-12}}m$
- Substitute all the known values in the above de-Broglie equation to get the velocity of the photon associated with the 800 pm wavelength.
\[\begin{align}
& v=\dfrac{h}{m\times v} \\
& v=\dfrac{6.626\times {{10}^{-34}}}{(1.675\times {{10}^{-27}})(800\times {{10}^{-12}})} \\
& v=4.94\times {{10}^{4}}m/\sec \\
\end{align}\]
- The velocity of the photon associated with the 800 pm wavelength in a neutron diffraction microscope is $4.94\times {{10}^{4}}m/\sec $ .
Note: Neutron diffraction is used to conclude the static structure for gases and amorphous solids. Maximum experiments aim to find the structure of crystalline solids using neutron diffraction microscopy in crystallography. Neutron diffraction microscope and electron diffraction are closely related to X-ray diffraction studies.
As per de-Broglie equation the relationship is as follows.
\[\lambda =\dfrac{h}{m\times v}\text{ (}or)\text{ }v=\dfrac{h}{m\times v}\]
Where h = Planck’s constant
m = mass of the neutron
v = Velocity of the neutron
$\lambda $ = Wavelength of the neutron.
Complete step by step answer:
- In the question it is given that in a neutron diffraction microscope the wavelength used is 800 pm, and we have to calculate the characteristic velocity associated with the neutron.
- From the de-Broglie equation we can calculate the velocity of the neutron by using the wavelength of the neutron and it is as follows.
\[v=\dfrac{h}{m\times v}\]
Where h = Planck’s constant = $6.626\times {{10}^{-34}}$
m = mass of the neutron = $1.675\times {{10}^{-27}}Kg$
v = Velocity of the neutron
$\lambda $ = Wavelength of the neutron = 800 pm = $800\times {{10}^{-12}}m$
- Substitute all the known values in the above de-Broglie equation to get the velocity of the photon associated with the 800 pm wavelength.
\[\begin{align}
& v=\dfrac{h}{m\times v} \\
& v=\dfrac{6.626\times {{10}^{-34}}}{(1.675\times {{10}^{-27}})(800\times {{10}^{-12}})} \\
& v=4.94\times {{10}^{4}}m/\sec \\
\end{align}\]
- The velocity of the photon associated with the 800 pm wavelength in a neutron diffraction microscope is $4.94\times {{10}^{4}}m/\sec $ .
Note: Neutron diffraction is used to conclude the static structure for gases and amorphous solids. Maximum experiments aim to find the structure of crystalline solids using neutron diffraction microscopy in crystallography. Neutron diffraction microscope and electron diffraction are closely related to X-ray diffraction studies.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

