Solve graphically the following systems of linear equations. Also find the coordinates of the points where the line meets the axis of y.
$
3x + 2y = 12 \\
5x - 2y = 4 \\
$
Answer
681.6k+ views
Hint:- In this question first we have to find at least two points on given lines to plot their lines on a graph. After plotting lines on graphs using obtained points, we have to find the point where these two lines intersect because it is the solution of a given system of linear equations.
Complete step-by-step answer:
We have, two lines of equations:
$
3x + 2y = 12 {\text{ eq}}{\text{.1 }} \\
5x - 2y = 4 {\text{ eq}}{\text{.2}} \\
$
Now, we have to plot given equations on a graph ; for this we require at least two points which lie on that line.
So, consider eq.1
$3x + 2y = 12{\text{ }}$
Now, put x=0 in eq.1, we get
$
\Rightarrow 2y = 12 \\
\Rightarrow y = 6 \\
$
Therefore, (0,6) lies on above line $3x + 2y = 12$.
Now, put y=0 in eq.1, we get
$
\Rightarrow 3x = 12 \\
\Rightarrow x = 4 \\
$
Therefore, (4,0) lies on line $3x + 2y = 12$.
Now put x=2 in eq.1, we get
$
\Rightarrow 3 \times 2 + 2y = 12 \\
\Rightarrow 2y = 6 \\
\Rightarrow y = 3 \\
$
Therefore, (2,3) lies on line $3x + 2y = 12$.
Now, consider eq.2
$5x - 2y = 4$
Now, put x=0 in eq.2, we get
$
\Rightarrow 0 - 2y = 4 \\
\Rightarrow y = - 2 \\
$
Therefore, (0,-2) lies on above line $5x - 2y = 4$.
Now, put y=0 in eq.2, we get
$
\Rightarrow 5x - 0 = 4 \\
\Rightarrow x = \left( {\dfrac{4}{5}} \right) \\
$
Therefore, $\left( {\dfrac{4}{5},0} \right)$ lies on line $5x - 2y = 4$.
Now put x=2 in eq.2, we get
$
\Rightarrow 5 \times 2 - 2y = 4 \\
\Rightarrow 2y = 6 \\
\Rightarrow y = 3 \\
$
Therefore, (2,3) lies on line $5x - 2y = 4$.
Now, plot given lines on a graph using obtained points.
Hence, from the graph we can see that x=2 and y=3 is the solution of the given system of equations.
We can also observe that line $3x + 2y = 12$ meet the y-axis at point (0,6).
And the line $5x - 2y = 4$ meet the y-axis at point (0,-2).
Note:- Whenever you get this type of question the key concept to solve this is to learn the concept of a system of linear equations containing two equations. The solution of such a system is the ordered pair that is a solution to both the equations of the system. Graphically, the solution is the intersection point where both lines of the system intersect.
Complete step-by-step answer:
We have, two lines of equations:
$
3x + 2y = 12 {\text{ eq}}{\text{.1 }} \\
5x - 2y = 4 {\text{ eq}}{\text{.2}} \\
$
Now, we have to plot given equations on a graph ; for this we require at least two points which lie on that line.
So, consider eq.1
$3x + 2y = 12{\text{ }}$
Now, put x=0 in eq.1, we get
$
\Rightarrow 2y = 12 \\
\Rightarrow y = 6 \\
$
Therefore, (0,6) lies on above line $3x + 2y = 12$.
Now, put y=0 in eq.1, we get
$
\Rightarrow 3x = 12 \\
\Rightarrow x = 4 \\
$
Therefore, (4,0) lies on line $3x + 2y = 12$.
Now put x=2 in eq.1, we get
$
\Rightarrow 3 \times 2 + 2y = 12 \\
\Rightarrow 2y = 6 \\
\Rightarrow y = 3 \\
$
Therefore, (2,3) lies on line $3x + 2y = 12$.
Now, consider eq.2
$5x - 2y = 4$
Now, put x=0 in eq.2, we get
$
\Rightarrow 0 - 2y = 4 \\
\Rightarrow y = - 2 \\
$
Therefore, (0,-2) lies on above line $5x - 2y = 4$.
Now, put y=0 in eq.2, we get
$
\Rightarrow 5x - 0 = 4 \\
\Rightarrow x = \left( {\dfrac{4}{5}} \right) \\
$
Therefore, $\left( {\dfrac{4}{5},0} \right)$ lies on line $5x - 2y = 4$.
Now put x=2 in eq.2, we get
$
\Rightarrow 5 \times 2 - 2y = 4 \\
\Rightarrow 2y = 6 \\
\Rightarrow y = 3 \\
$
Therefore, (2,3) lies on line $5x - 2y = 4$.
Now, plot given lines on a graph using obtained points.
Hence, from the graph we can see that x=2 and y=3 is the solution of the given system of equations.
We can also observe that line $3x + 2y = 12$ meet the y-axis at point (0,6).
And the line $5x - 2y = 4$ meet the y-axis at point (0,-2).
Note:- Whenever you get this type of question the key concept to solve this is to learn the concept of a system of linear equations containing two equations. The solution of such a system is the ordered pair that is a solution to both the equations of the system. Graphically, the solution is the intersection point where both lines of the system intersect.
Recently Updated Pages
What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

A Paragraph on Pollution in about 100-150 Words

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

Name 10 Living and Non living things class 9 biology CBSE

What is the full form of pH?

What is pollution? How many types of pollution? Define it

On an outline map of India show its neighbouring c class 9 social science CBSE

