The average temperature of the first three days of the week is ${{27}^{\circ }}C$ and the next three days is ${{29}^{\circ }}C$. If the weekly average is ${{28.5}^{\circ }}C$, what is the temperature on the last day?
(A) ${{31.5}^{\circ }}C$
(B) ${{28}^{\circ }}C$
(C) ${{21}^{\circ }}C$
(D) ${{42}^{\circ }}C$
Answer
649.5k+ views
Hint: We solve this question by first assuming the temperatures on first three days as ${{x}_{1}},{{x}_{2}},{{x}_{3}}$ and temperatures on next three days as ${{x}_{4}},{{x}_{5}},{{x}_{6}}$ and the temperature on last day as $X$. Then we consider the formula for average, $Average=\dfrac{Sum\ of\,observations}{Total\ number\ of\ observations}$ and find the value of sum of temperatures on the first three days and then sum of temperatures on the next three days. Then we add them to find the value of the sum of temperatures on the first six days. Then we use the same formula to find the sum of temperatures on all seven days. Then we substitute the value of the sum of temperatures on the first six days in the equation obtained and find the value of temperature on the last day.
Complete step by step answer:
We are given that the average temperature of the first three days of the week is ${{27}^{\circ }}C$. Let the temperatures on those days be ${{x}_{1}},{{x}_{2}},{{x}_{3}}$.
We are also given that the average temperature of the next three days of the week is ${{29}^{\circ }}C$. Let the temperatures on those days be ${{x}_{4}},{{x}_{5}},{{x}_{6}}$.
We are also given that the weekly average is ${{28.5}^{\circ }}C$.
We need to find the temperature on the last day. Let that temperature be $X$.
Now let us consider the formula for average.
$Average=\dfrac{Sum\ of\,observations}{Total\ number\ of\ observations}$
As we are given that average temperature of first three days of the week is ${{27}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}=27 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}=81..........\left( 1 \right) \\
\end{align}$
As we are given that average temperature of next three days of the week is ${{29}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{4}}+{{x}_{5}}+{{x}_{6}}}{3}=29 \\
& \Rightarrow {{x}_{4}}+{{x}_{5}}+{{x}_{6}}=87..........\left( 2 \right) \\
\end{align}$
Now let us add the values from equations (1) and (2). Then we get,
$\begin{align}
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=81+87 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=168.........\left( 3 \right) \\
\end{align}$
As we are also given that the weekly average is ${{28.5}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X}{7}=28.5 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X=199.5 \\
\end{align}$
Now let us substitute the value obtained in equation (3) in the above equation. Then we get,
$\begin{align}
& \Rightarrow 168+X=199.5 \\
& \Rightarrow X=199.5-168 \\
& \Rightarrow X=31.5 \\
\end{align}$
So, we get the temperature of the last day as ${{31.5}^{\circ }}C$.
Hence the answer is Option A.
Note:
While solving this question one might wrongly interpret the given information by taking the given information, the average temperature of first three days is ${{27}^{\circ }}C$ as, the temperature on all three days is ${{27}^{\circ }}C$. It gives the same answer but the interpretation is wrong. Here the temperature on the three days can be different but their average is ${{27}^{\circ }}C$.
Complete step by step answer:
We are given that the average temperature of the first three days of the week is ${{27}^{\circ }}C$. Let the temperatures on those days be ${{x}_{1}},{{x}_{2}},{{x}_{3}}$.
We are also given that the average temperature of the next three days of the week is ${{29}^{\circ }}C$. Let the temperatures on those days be ${{x}_{4}},{{x}_{5}},{{x}_{6}}$.
We are also given that the weekly average is ${{28.5}^{\circ }}C$.
We need to find the temperature on the last day. Let that temperature be $X$.
Now let us consider the formula for average.
$Average=\dfrac{Sum\ of\,observations}{Total\ number\ of\ observations}$
As we are given that average temperature of first three days of the week is ${{27}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}=27 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}=81..........\left( 1 \right) \\
\end{align}$
As we are given that average temperature of next three days of the week is ${{29}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{4}}+{{x}_{5}}+{{x}_{6}}}{3}=29 \\
& \Rightarrow {{x}_{4}}+{{x}_{5}}+{{x}_{6}}=87..........\left( 2 \right) \\
\end{align}$
Now let us add the values from equations (1) and (2). Then we get,
$\begin{align}
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=81+87 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=168.........\left( 3 \right) \\
\end{align}$
As we are also given that the weekly average is ${{28.5}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X}{7}=28.5 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X=199.5 \\
\end{align}$
Now let us substitute the value obtained in equation (3) in the above equation. Then we get,
$\begin{align}
& \Rightarrow 168+X=199.5 \\
& \Rightarrow X=199.5-168 \\
& \Rightarrow X=31.5 \\
\end{align}$
So, we get the temperature of the last day as ${{31.5}^{\circ }}C$.
Hence the answer is Option A.
Note:
While solving this question one might wrongly interpret the given information by taking the given information, the average temperature of first three days is ${{27}^{\circ }}C$ as, the temperature on all three days is ${{27}^{\circ }}C$. It gives the same answer but the interpretation is wrong. Here the temperature on the three days can be different but their average is ${{27}^{\circ }}C$.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

Draw a labelled diagram of the neuron and describe class 11 biology CBSE

