The curve represented by the differential equation \[xdy - ydx = ydy\], intersects the y-axis at A (0,1) and the line \[y = e\] at (a, b,), then the value of \[\left( {a + b} \right)\] is
Answer
617.7k+ views
Hint: A differential equation is an equation which contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable), as to find out the value of \[\left( {a + b} \right)\], differentiate the given equation with respect to y and apply logarithmic functions to solve the function.
Complete step by step solution:
The given differential equation is \[xdy - ydx = ydy\].
Divide both sides of the equation by \[{y^2}\] as
\[\dfrac{{xdy - ydx}}{{{y^2}}} = \dfrac{{ydy}}{{{y^2}}}\]
\[\Rightarrow\dfrac{{xdy - ydx}}{{{y^2}}} = \dfrac{{dy}}{y}\]
As the differential equation intersects the y-axis
\[\dfrac{{ydx - xdy}}{{{y^2}}} = - \dfrac{{dy}}{y}\]
\[\Rightarrow d\left( {\dfrac{x}{y}} \right) = \dfrac{{ - dy}}{y}\]
Differentiating the terms, we get
\[\dfrac{x}{y} = - \log y + C\]
\[\Rightarrow\dfrac{x}{y} = \log \left( {\dfrac{1}{y}} \right) + C\]
$\Rightarrow 0 = 0 + C$
Implies that $C=0$.
Now substitute y=e in
\[\dfrac{x}{y} = \log \left( {\dfrac{1}{y}} \right)\]
\[\Rightarrow\dfrac{x}{e} = \log \left( {\dfrac{1}{e}} \right)\]
After differentiating we get the value of x as
\[\dfrac{x}{e} = - 1\]
\[\Rightarrow x = - e\], \[\left( { - e,e} \right)\]
\[\therefore\left( {a + b} \right)= 0 \]
Hence, \[\left( {a + b} \right)\] is zero.
Additional information:
Order of Differential Equation: The order of the highest order derivative present in the differential equation is called the order of the equation. If the order of the differential equation is 1, then it is called first order. If the order of the equation is 2, then it is called a second-order, and so on.
Degree of Differential Equation: The degree of the differential equation is the power of the highest order derivative, where the original equation is represented in the form of a polynomial equation in derivatives such as \[y'\], \[y''\],\[y'''\] and so on.
Note: A differential equation contains derivatives which are either partial derivatives or ordinary derivatives. The derivative represents a rate of change, and the differential equation describes a relationship between the quantity that is continuously varying with respect to the change in another quantity.
Complete step by step solution:
The given differential equation is \[xdy - ydx = ydy\].
Divide both sides of the equation by \[{y^2}\] as
\[\dfrac{{xdy - ydx}}{{{y^2}}} = \dfrac{{ydy}}{{{y^2}}}\]
\[\Rightarrow\dfrac{{xdy - ydx}}{{{y^2}}} = \dfrac{{dy}}{y}\]
As the differential equation intersects the y-axis
\[\dfrac{{ydx - xdy}}{{{y^2}}} = - \dfrac{{dy}}{y}\]
\[\Rightarrow d\left( {\dfrac{x}{y}} \right) = \dfrac{{ - dy}}{y}\]
Differentiating the terms, we get
\[\dfrac{x}{y} = - \log y + C\]
\[\Rightarrow\dfrac{x}{y} = \log \left( {\dfrac{1}{y}} \right) + C\]
$\Rightarrow 0 = 0 + C$
Implies that $C=0$.
Now substitute y=e in
\[\dfrac{x}{y} = \log \left( {\dfrac{1}{y}} \right)\]
\[\Rightarrow\dfrac{x}{e} = \log \left( {\dfrac{1}{e}} \right)\]
After differentiating we get the value of x as
\[\dfrac{x}{e} = - 1\]
\[\Rightarrow x = - e\], \[\left( { - e,e} \right)\]
\[\therefore\left( {a + b} \right)= 0 \]
Hence, \[\left( {a + b} \right)\] is zero.
Additional information:
Order of Differential Equation: The order of the highest order derivative present in the differential equation is called the order of the equation. If the order of the differential equation is 1, then it is called first order. If the order of the equation is 2, then it is called a second-order, and so on.
Degree of Differential Equation: The degree of the differential equation is the power of the highest order derivative, where the original equation is represented in the form of a polynomial equation in derivatives such as \[y'\], \[y''\],\[y'''\] and so on.
Note: A differential equation contains derivatives which are either partial derivatives or ordinary derivatives. The derivative represents a rate of change, and the differential equation describes a relationship between the quantity that is continuously varying with respect to the change in another quantity.
Recently Updated Pages
What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

A Paragraph on Pollution in about 100-150 Words

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

