The gas that develops cracks in rubber is:
[A] ${{O}_{2}}$
[B] ${{O}_{3}}$
[C] $C{{O}_{2}}$
[D] $S{{O}_{2}}$
Answer
633.3k+ views
Hint: We know that rubber is a polymeric chain of different hydrocarbons. Attack of a certain gas affects the circumference of the material and causes it to crack. Chemically, the gas affects the double bonds of the material by cleaving it by formation of ozonide.
Complete answer:
Before answering this, let us discuss what rubber is and its types.
We should know that rubber is an elastic substance and it can be obtained naturally as well as synthetically.
The rubber that we obtain from certain tropical plants is known as natural rubber. We can also manufacture rubber from natural gas and petroleum and other derived hydrocarbons. This is known as synthetic rubber.
Natural rubber has high tensile strength and higher tear resistance compared to synthetic rubber but vulcanization of synthetic rubber makes it stronger.
Now, let us discuss the given question.
We know that rubber changes its properties when exposed to changing environment conditions.
In the elastomers like natural rubber, styrene – butadiene rubber etc. we often notice certain cracks in the surface. These cracks are formed due to ozone attacking the double bonds of the polymer chain and undergoing ozonolysis. It forms cracks at right angles to the strain axis and thus affect the circumference of the material.
Now let us discuss the process of ozonolysis-
Ozonolysis is the process of cleaving the double bond by the formation of a five membered ring. The formation of ozonide results in cleaving of the double bond and thus breaking of the double bond to give two separated products. We can show the reaction as-
\[{{R}_{1}}{{R}_{2}}C=C{{R}_{3}}{{R}_{4}}\xrightarrow{{{O}_{3}}}{{R}_{1}}{{R}_{2}}CO+{{R}_{3}}{{R}_{4}}CO\]
Here, the alkyl groups are denoted by R.
We can understand from the above discussion that crack in rubber is formed due to the action of ozone.
Therefore, the correct answer is option [B] ${{O}_{3}}$ .
Note:
Although 60% of the rubber industry is based upon synthetic rubber, the remaining 40% is still taken by natural rubber. Natural rubber is used in high performance racing tires and also for aircrafts and buses due to its strength. However, it does not perform well outdoors due to its lack of resistance towards heat aging caused by sunlight and also ozone cracking.
Complete answer:
Before answering this, let us discuss what rubber is and its types.
We should know that rubber is an elastic substance and it can be obtained naturally as well as synthetically.
The rubber that we obtain from certain tropical plants is known as natural rubber. We can also manufacture rubber from natural gas and petroleum and other derived hydrocarbons. This is known as synthetic rubber.
Natural rubber has high tensile strength and higher tear resistance compared to synthetic rubber but vulcanization of synthetic rubber makes it stronger.
Now, let us discuss the given question.
We know that rubber changes its properties when exposed to changing environment conditions.
In the elastomers like natural rubber, styrene – butadiene rubber etc. we often notice certain cracks in the surface. These cracks are formed due to ozone attacking the double bonds of the polymer chain and undergoing ozonolysis. It forms cracks at right angles to the strain axis and thus affect the circumference of the material.
Now let us discuss the process of ozonolysis-
Ozonolysis is the process of cleaving the double bond by the formation of a five membered ring. The formation of ozonide results in cleaving of the double bond and thus breaking of the double bond to give two separated products. We can show the reaction as-
\[{{R}_{1}}{{R}_{2}}C=C{{R}_{3}}{{R}_{4}}\xrightarrow{{{O}_{3}}}{{R}_{1}}{{R}_{2}}CO+{{R}_{3}}{{R}_{4}}CO\]
Here, the alkyl groups are denoted by R.
We can understand from the above discussion that crack in rubber is formed due to the action of ozone.
Therefore, the correct answer is option [B] ${{O}_{3}}$ .
Note:
Although 60% of the rubber industry is based upon synthetic rubber, the remaining 40% is still taken by natural rubber. Natural rubber is used in high performance racing tires and also for aircrafts and buses due to its strength. However, it does not perform well outdoors due to its lack of resistance towards heat aging caused by sunlight and also ozone cracking.
Recently Updated Pages
Which of the following graphs shows the variation of class 12 physics CBSE

Draw a labelled diagram of the human male reproductive class 12 biology CBSE

Describe the experiment to compare the emf of two cells class 12 physics CBSE

What is standard hydrogen electrode

What is conventional current and electric current class 12 physics CBSE

2Bromopentane is treated with an alcoholic KOH solution class 12 chemistry CBSE

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

